Statistics-Class-10-Mode of Grouped Data-Lessonplan

Mode of Grouped Data | Grade 10 Mathematics

Mode of Grouped Data

Grade 10 Mathematics | AP/TS/NCERT - Period 13.5

Formula for Mode of Grouped Data

Mode = l +
f₁ - f₀ 2f₁ - f₀ - f₂
× h

Where: l = lower boundary of modal class, h = class size, f₁ = frequency of modal class,
f₀ = frequency of class preceding modal class, f₂ = frequency of class succeeding modal class

Worked Examples

Example 5

A survey conducted on 20 households in a locality by a group of students resulted in the following frequency table:

Family size 1-3 3-5 5-7 7-9 9-11
Number of families 7 8 2 2 1

Find the mode of this data.

Step 1: Identify the modal class (class with highest frequency)

The maximum class frequency is 8, and the class corresponding to this frequency is 3-5.

So, the modal class is 3-5.

Step 2: Identify the values needed for the formula:

l = lower boundary of modal class = 3

h = class size = 2

f₁ = frequency of modal class = 8

f₀ = frequency of class preceding modal class = 7

f₂ = frequency of class succeeding modal class = 2

Step 3: Apply the formula:

Mode = l +
f₁ - f₀ 2f₁ - f₀ - f₂
× h
= 3 +
8 - 7 2×8 - 7 - 2
× 2
= 3 +
1 16 - 9
× 2
= 3 +
1 7
× 2
= 3 +
2 7
= 3 + 0.286 = 3.286

Step 4: Interpretation

Therefore, the mode of the data is 3.286.

Practice Exercises

Exercise 1

The following table shows the ages of the patients admitted in a hospital during a year:

Age (in years) 5-15 15-25 25-35 35-45 45-55 55-65
No. of patients 6 11 21 23 14 5

Find the mode of the data.

Step 1: Identify the modal class

The highest frequency is 23, which corresponds to the class 35-45.

So, the modal class is 35-45.

Step 2: Identify the values:

l = lower boundary of modal class = 35

h = class size = 10

f₁ = frequency of modal class = 23

f₀ = frequency of class preceding modal class = 21

f₂ = frequency of class succeeding modal class = 14

Step 3: Apply the formula:

Mode = l +
f₁ - f₀ 2f₁ - f₀ - f₂
× h
= 35 +
23 - 21 2×23 - 21 - 14
× 10
= 35 +
2 46 - 35
× 10
= 35 +
2 11
× 10
= 35 +
20 11
= 35 + 1.818 = 36.818

Step 4: Interpretation

Therefore, the mode of the data is 36.818.

Exercise 2

The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Lifetimes (in hours) 0-20 20-40 40-60 60-80 80-100 100-120
Frequency 10 35 52 61 38 29

Determine the modal lifetimes of the components.

Step 1: Identify the modal class

The highest frequency is 61, which corresponds to the class 60-80.

So, the modal class is 60-80.

Step 2: Identify the values:

l = lower boundary of modal class = 60

h = class size = 20

f₁ = frequency of modal class = 61

f₀ = frequency of class preceding modal class = 52

f₂ = frequency of class succeeding modal class = 38

Step 3: Apply the formula:

Mode = l +
f₁ - f₀ 2f₁ - f₀ - f₂
× h
= 60 +
61 - 52 2×61 - 52 - 38
× 20
= 60 +
9 122 - 90
× 20
= 60 +
9 32
× 20
= 60 +
180 32
= 60 + 5.625 = 65.625

Step 4: Interpretation

Therefore, the modal lifetime of the components is 65.625 hours.

Grade 10 Mathematics - Statistics | Mode of Grouped Data

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