Statistics-Class-10-Step Deviation Method -for Mean of Grouped Data -Grade 10 -Mathematics - Period 13.4

Step Deviation Method for Mean

Step Deviation Method for Mean of Grouped Data

Grade 10 Mathematics - Period 13.4

Recall Previous Methods

Direct Method: \(\bar{x} = \frac{\sum f_i x_i}{\sum f_i}\)
Assumed Mean Method: \(\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i}\) where \(d_i = x_i - a\)

Introduce Step Deviation Method

\(\bar{x} = a + \frac{\sum f_i u_i}{\sum f_i} \times h\)

Where:

\(a\) = assumed mean

\(h\) = class size

\(u_i = \frac{x_i - a}{h}\)

\(f_i\) = frequency

When to Use Step Deviation

  • When \(x_i\) and \(d_i\) values are large
  • To simplify calculations, especially with large numbers

Example: Daily Expenditure on Food

Daily expenditure (in ₹) 100-150 150-200 200-250 250-300 300-350
Number of households 4 5 12 2 2

Solution:

Class Interval Frequency (\(f_i\)) Midpoint (\(x_i\)) \(u_i = \frac{x_i - a}{h}\) \(f_i u_i\)
100-150 4 125 -2 -8
150-200 5 175 -1 -5
200-250 12 225 (a) 0 0
250-300 2 275 1 2
300-350 2 325 2 4
Total \(\sum f_i = 25\) \(\sum f_i u_i = -7\)
\(\bar{x} = a + \frac{\sum f_i u_i}{\sum f_i} \times h = 225 + \frac{-7}{25} \times 50 = 225 + (-14) = 211\)

∴ The mean daily expenditure of a household is ₹ 211.

Practice Problem

Literacy rate (in %) 45-55 55-65 65-75 75-85 85-95
Number of cities 3 10 11 8 3

Find the mean literacy rate using the step deviation method.

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